Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 328: 83

Answer

$874m$

Work Step by Step

We know that $r_{min}=\frac{v^2}{(a_{cp})_{max}}$ We plug in the known values to obtain: $r_{min}=\frac{(245m/s)^2}{7\times 9.81m/s^2}$ $r_{min}=874m$
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