Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 328: 82

Answer

$1.4m/s$

Work Step by Step

We know that $v=\sqrt{\frac{K}{m}}$ We plug in the known values to obtain: $v=\sqrt{\frac{0.12J}{0.065Kg}}$ $v=1.4m/s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.