Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 328: 80

Answer

$1 hr, 24 \space min$

Work Step by Step

We know that $T=\frac{2\pi}{\omega}$ $\implies T=\frac{2\pi}{\sqrt{\frac{g}{R}}}$ We plug in the known values to obtain: $T=\frac{2\pi}{\sqrt{9.81(6.37\times 10^6)}}$ $T=5060s=1 hr, 24 \space min$
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