Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 10 - Rotational Kinematics and Energy - Problems and Conceptual Exercises - Page 328: 81

Answer

$6.8rad/s$

Work Step by Step

We know that $\Delta \theta=2\frac{1}{2}rev$ $\implies \Delta \theta=2.5rev$ Now $\omega=\frac{\Delta \theta}{t}$ We plug in the known values to obtain: $\omega=\frac{2.5rev}{2.3s}$ $\implies \omega=1.0869rev/s$ $\implies \omega=(1.0869rev/s)(\frac{2\pi \space rad}{1rev})$ $\omega=6.8rad/s$
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