Answer
a. 66 V/m
b. 5.8 W/m$^2$
Work Step by Step
a. Use equation 22–2.
$$c=\frac{E}{B}$$
Here, E and B are the magnitudes of the electric and magnetic fields at the same point in space. Both fields reach their maximum at the same place.
$$E=Bc=(2.2\times10^{-7}T)(3.00\times10^8m/s)=66V/m$$
b. Find the intensity using equation 22-8.
$$\overline{I}=\frac{E_oB_o}{2\mu_o}$$
$$=\frac{E_oB_o}{2\mu_o}=\frac{(66V/m)(2.2\times10^{-7}T)}{2(4 \pi\times10^{-7}Tm/A)}$$
$$=5.8W/m^2$$
