Answer
$4.2\times10^{14}Hz$
Work Step by Step
Use equation 22–4, $c=\lambda f$.
$$f=\frac{c}{\lambda}=\frac{3.00\times10^8m/s }{720\times10^{-9}m}$$
$$f=4.2\times10^{14}Hz$$
This is visible light, on the red end of the spectrum.
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 22 - Electromagnetic Waves - Problems - Page 641: 10
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