Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 22 - Electromagnetic Waves - Problems - Page 641: 15

Answer

a. $\lambda=1.318\times10^{-2}m$ b. $f=2.5\times10^{18}Hz$

Work Step by Step

a. Use equation 22–4, $c=\lambda f$. $$\lambda=\frac{c}{f}=\frac{2.998\times10^8m/s }{22.75\times10^{9}Hz}$$ $$\lambda=1.318\times10^{-2}m$$ b. Use equation 22–4, $c=\lambda f$. $$f=\frac{c}{\lambda}=\frac{3.00\times10^8m/s }{0.12\times10^{-9}m}$$ $$f=2.5\times10^{18}Hz$$
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