Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 22 - Electromagnetic Waves - Problems - Page 641: 25

Answer

See answers.

Work Step by Step

The intensity is the power per unit area. The 1800W of power is distributed uniformly over the surface area of the sphere. $$\overline{I}=\frac{P}{A}=\frac{1800W}{4\pi (5.0m)^2}=5.7\frac{W}{m^2}$$ The energy per unit area per unit time is the magnitude of the average intensity, equation 22–8. Find the rms value of the electric field. $$\overline{I}=\frac{1}{2}\epsilon_ocE_o^2=\frac{1}{2}\epsilon_oc(\sqrt{2}E_{rms})^2=\epsilon_ocE_{rms}^2$$ $$E_{rms}=\sqrt{\frac{\overline{I}}{\epsilon_oc }}$$ $$=\sqrt{\frac{5.730W/m^2}{(8.85\times10^{-12} C^2/(N\cdot m^2))(3.00\times10^8m/s)}}=46V/m$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.