Answer
(a) $i = 50~mA$
(b) $i = 50~mA$
Work Step by Step
Note that the peak current does not depend on the frequency.
(a) We can find the peak current:
$i = \frac{emf}{R}$
$i = \frac{10~V}{200~\Omega}$
$i = 0.050~A$
$i = 50~mA$
(b) We can find the peak current:
$i = \frac{emf}{R}$
$i = \frac{10~V}{200~\Omega}$
$i = 0.050~A$
$i = 50~mA$