Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 35 - AC Circuits - Exercises and Problems - Page 1052: 5

Answer

(a) $i = 50~mA$ (b) $i = 50~mA$

Work Step by Step

Note that the peak current does not depend on the frequency. (a) We can find the peak current: $i = \frac{emf}{R}$ $i = \frac{10~V}{200~\Omega}$ $i = 0.050~A$ $i = 50~mA$ (b) We can find the peak current: $i = \frac{emf}{R}$ $i = \frac{10~V}{200~\Omega}$ $i = 0.050~A$ $i = 50~mA$
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