Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 35 - AC Circuits - Exercises and Problems - Page 1052: 29

Answer

$R = 9.6~\Omega$

Work Step by Step

We can find the resistance: $P = \frac{V^2}{R}$ $R = \frac{V^2}{P}$ $R = \frac{(120~V)^2}{1500~W}$ $R = 9.6~\Omega$
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