Answer
$C = 1.59\times 10^{-6}~F$
Work Step by Step
We can find the value of the capacitor:
$f = \frac{1}{2\pi ~R~C}$
$C = \frac{1}{2\pi ~R~f}$
$C = \frac{1}{(2\pi) ~(100 ~\Omega)~(1000~Hz)}$
$C = 1.59\times 10^{-6}~F$
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