Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 35 - AC Circuits - Exercises and Problems - Page 1052: 13

Answer

$C = 1.59\times 10^{-6}~F$

Work Step by Step

We can find the value of the capacitor: $f = \frac{1}{2\pi ~R~C}$ $C = \frac{1}{2\pi ~R~f}$ $C = \frac{1}{(2\pi) ~(100 ~\Omega)~(1000~Hz)}$ $C = 1.59\times 10^{-6}~F$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.