Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 33 - Electromagnetic Induction - Exercises and Problems - Page 1001: 72

Answer

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Work Step by Step

The maximum energy stored in the capacitor, in $LC$ circuits, is equal to the maximum energy stored in the inductor since the energy in the circuit alternates between the inductor and the capacitor. So $$(U_L)_{\rm max}=\frac{1}{2}LI_{\rm max}^2 =(U_C )_{\rm max}$$ So, $$L=\dfrac{2(U_C )_{\rm max}}{I_{\rm max}^2}$$ Plug the known; $$L=\dfrac{2(1\times 10^{-5})}{(0.1)^2}$$ $$L=\color{red}{\bf 2.0}\;\rm mH$$ Recalling that $$\omega=2\pi f=\dfrac{1}{\sqrt{LC}}$$ Hence, $$C=\dfrac{1}{4\pi^2f^2L} $$ Plug the known; $$C=\dfrac{1}{4\pi^2(10\times 10^3)^2(2\times 10^{-3})}$$ $$C=\color{red}{\bf 0.127}\;\rm \mu F $$
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