Answer
$93KJ$
Work Step by Step
We can find the required thermal energy as follows:
$E=3Nk_BT$
We plug in the known values to obtain:
$E=3\times 10\times 6.023\times 10^{23}\times 1.38\times 10^{-23}\times 373$
This simplifies to:
$E=9.3\times 10^4J=93KJ$
