Answer
$-273.1C^{\circ}$
Work Step by Step
We can determine the required temperature as follows:
$T=\frac{Mv_{rms}^2}{3N_Ak_B}$
We plug in the known values to obtain:
$T=\frac{0.028(1.5)^2}{3\times 6.02\times 10^{23}\times 1.38\times 10^{-23}}$
This simplifies to:
$T=0.0025K=-273.1C^{\circ}$
