Answer
$110C^{\circ}$
Work Step by Step
We can determine the required temperature as follows:
$T=(\frac{P}{A\sigma}+T_a^4)^{\frac{1}{4}}$
We plug in the known values to obtain:
$T=(\frac{800}{1(5.67\times 10^{-8}) }+(293)^4)^{\frac{1}{4}}$
This simplifies to:
$T=383K=110C^{\circ}$
