Answer
$26.25C^{\circ}$
Work Step by Step
The air temperature inside the box can be determined as follows:
$T=\frac{PL}{KA}+T_a$
We plug in the known values to obtain:
$T=\frac{100(0.012)}{(0.8)(6)(0.2)^2}+20$
$\implies T=26.25C^{\circ}$
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