Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 15 - Fluids and Elasticity - Exercises and Problems: 24

Answer

The fluid's speed in the circular part of the tube is $1.27~v_0$

Work Step by Step

The volume flow rate is constant throughout the tube. The volume flow rate is the speed of the fluid times the cross-sectional area of the tube. We can find the fluid's speed $v_2$ in the circular part of the tube as: $v_2~A_2 = v_0~A_0$ $v_2~\pi~(\frac{L}{2})^2 = v_0~L^2$ $v_2 = \frac{4~v_0~L^2}{\pi~L^2}$ $v_2 = \frac{4~v_0}{\pi}$ $v_2 = 1.27~v_0$ The fluid's speed in the circular part of the tube is $1.27~v_0$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.