The force required to pull the cover off is 630 N
Work Step by Step
We can find the pressure difference between the pressure on the inside of the cover and the pressure on the outside of the cover. $\Delta P = P_0 - P_i$ $\Delta P = (1.01\times 10^5~Pa)-(2.0\times 10^4~Pa)$ $\Delta P = 8.01\times 10^4~Pa$ Then we find the force required to pull off the cover. $F = (\Delta P)~(Area~of~the~hole)$ $F = (8.01\times 10^4~N/m^2)(\pi)(0.05~m)^2$ $F = 630~N$ The force required to pull the cover off is 630 N.