Answer
The force required to pull the cover off is 630 N
Work Step by Step
We can find the pressure difference between the pressure on the inside of the cover and the pressure on the outside of the cover.
$\Delta P = P_0 - P_i$
$\Delta P = (1.01\times 10^5~Pa)-(2.0\times 10^4~Pa)$
$\Delta P = 8.01\times 10^4~Pa$
Then we find the force required to pull off the cover.
$F = (\Delta P)~(Area~of~the~hole)$
$F = (8.01\times 10^4~N/m^2)(\pi)(0.05~m)^2$
$F = 630~N$
The force required to pull the cover off is 630 N.
