## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Young's modulus for the rope is $5.5\times 10^9~N/m^2$
We can find Young's modulus for the rope as: $Y = \frac{F/A}{\Delta~L/L}$ $Y = \frac{F~L}{A~\Delta L}$ $Y = \frac{(70~kg)(9.80~m/s^2)(50~m)}{(\pi)(5.0\times 10^{-3}~m)^2(0.080~m)}$ $Y = 5.5\times 10^9~N/m^2$ Young's modulus for the rope is $5.5\times 10^9~N/m^2$.