Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 6 - Chemical Composition - Exercises - Problems - Page 197: 22

Answer

a) $1.595 moles Cr$ b) $9.15\times10^{18} atoms Fe$ c) $2.198\times10^{22} atoms Ti$ d) $ 0.181 moles Hg$

Work Step by Step

Using Avagadro's Number, we can simply convert between atoms and moles as shown below: a) $9.61\times10^{23} atoms Cr \times\frac{1 mole}{6.023\times10^{23} atoms} = 1.595 moles Cr$ b) $1.52\times10^{-5} moles Fe\times\frac{6.023\times10^{23} atoms}{1 mole} = 9.15\times10^{18} atoms Fe$ c) $0.0365 moles Ti\times\frac{6.023\times10^{23} atoms}{1 mole} = 2.198\times10^{22} atoms Ti$ d) $1.09\times10^{23} atoms Hg \times\frac{1 mole}{6.023\times10^{23} atoms} = 0.181 moles Hg$
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