Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 6 - Chemical Composition - Exercises - Problems - Page 197: 36

Answer

1.589 g Pt

Work Step by Step

1 mole = $6.022 \times 10^{23}$ atoms Number of mole = $\frac{atoms}{6.022 \times 10^{23}}$ = $\frac{4.91 \times 10^{21}}{6.022 \times 10^{23}}$ = 0.00815 mole Pt mass = number of moles $\times$ molar mass = $(0.00815 mol) \times (195 g/mol)$ = 1.589 g Pt
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