Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 6 - Chemical Composition - Exercises - Problems - Page 197: 31

Answer

a) $1.11 moles Ne$ b) $ 4.67 g Ar$ c) $ 7.62 moles Xe$ d) $ 5.76\times10^{-4} g He$

Work Step by Step

Using the molar mass of the element provided, we can simply convert from grams to moles or vice-versa; a) $22.5 g Ne\times\frac{1 mole Ne}{20.18 g/mol} = 1.11 moles Ne$ b) $0.117 moles Ar \times\frac{39.948 g/mole}{1 mole Ar} = 4.67 g Ar$ c) $1kg = 1000g Xe\times\frac{1 mole Xe }{131.293 g/mole} = 7.62 moles Xe$ d) $1.44\times10^{-4} moles He\times\frac{4.00 g/mole}{1 mole He} = 5.76\times10^{-4} g He$
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