Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 6 - Chemical Composition - Exercises - Problems - Page 197: 21

Answer

a) $3.32\times10^{23} atoms Ne$ b) $5.40 moles Ar$ c) $1.07\times10^{24} atoms Xe$ d) $1.79\times10^{-4} moles He$

Work Step by Step

Using Avagadro's Number, we can simply convert between atoms and moles as shown below: a) $0.552 moles Ne\times\frac{6.023\times10^{23} atoms}{1 mole} = 3.32\times10^{23} atoms Ne$ b) $3.25\times10^{24} atoms Ar \times\frac{1 mole}{6.023\times10^{23} atoms} = 5.40 moles Ar$ c) $1.78moles Xe\times\frac{6.023\times10^{23} atoms}{1 mole} = 1.07\times10^{24} atoms Xe$ d) $1.08\times10^{20} atoms He \times\frac{1 mole}{6.023\times10^{23} atoms} = 1.79\times10^{-4} moles He$
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