Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 6 - Chemical Composition - Exercises - Problems - Page 197: 20

Answer

a) 7.63 mole Pb b) $4.67 \times 10^{-2}$ mole He c) 1.31 mole K d) $7.31 \times 10^{-3}$ mole Ca

Work Step by Step

1 mole of a substance contains $6.022 \times 10^{23}$ atoms. *** to convert atoms into moles we divide the number of moles by $6.022 \times 10^{23}$ a) $4.6 \times 10^{24}$ Pb atoms = $\frac{4.6 \times 10^{24} atoms}{6.022 \times 10^{23}}$ = 7.63 mole Pb b) $2.87 \times 10^{22}$ He atoms = $\frac{2.87 \times 10^{22} atoms}{6.022 \times 10^{23}}$ = $4.67 \times 10^{-2}$ mole He c) $7.9 \times 10^{23}$ K atoms = $\frac{7.9 \times 10^{23} atoms}{6.022 \times 10^{23}}$ = 1.31 mole K d) $4.41 \times 10^{21}$ Ca atoms = $\frac{4.41 \times 10^{21} atoms}{6.022 \times 10^{23}}$ = $7.31 \times 10^{-3}$ mole Ca
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