Answer
$101.8^{\circ}C$
Work Step by Step
$\Delta T_{f}=m\times K_{f}\implies m=\frac{\Delta T_{f}}{K_{f}}$
$\Delta T_{b}=m\times K_{b}=\frac{\Delta T_{f}}{K_{f}}\times K_{b}$
$=(\frac{6.7^{\circ}C}{1.86}\times0.512)^{\circ}C=1.8^{\circ}C$
Boiling point= $100.00^{\circ}C+1.8^{\circ}C=101.8^{\circ}C$
