Answer
0.43 L
Work Step by Step
$M_{1}V_{1}=M_{2}V_{2}$
$\implies M_{2}=\frac{M_{1}V_{1}}{V_{2}}=\frac{8.5\,M\times125\,mL}{2500\,mL}$
$=0.425\,M$
Molarity= $\frac{\text{moles solute}}{\text{liters solution}}=0.425\,M$
$\implies \text{liters solution}=\frac{\text{moles solute}}{0.425\,M}$
$=\frac{\frac{10.8\,g}{58.44\,g/mol}}{0.425\,M}=0.43\,L$
