Answer
Molarity= 2.28 M
Mass percent= $12.3\%$
Work Step by Step
Molarity=$ \frac{\text{moles solute}}{\text{volume of solution in L}}$
$=\frac{\frac{133\,g}{58.44\,g/mol}}{1.00\,L}=2.28\,M$
Mass percent= $\frac{\text{Mass of the solute}}{\text{Mass of the solution}}\times100\%$
$=\frac{133\,g}{1.08\,g/mL\times1000\,mL}\times100\%$
$=12.3\%$