Answer
Molarity= 0.583 M
Mass percent= 5.61%
Work Step by Step
Molarity=$ \frac{\text{moles solute}}{\text{volume of solution in L}}$
$=\frac{\frac{88.4\,g}{101.1\,g/mol}}{1.50\,L}=0.583\,M$
Mass percent= $\frac{\text{Mass of the solute}}{\text{Mass of the solution}}\times100\%$
$=\frac{88.4\,g}{1.05\,g/mL\times1500\,mL}\times100\%$
$=5.61\%$
