Answer
V = 2.4 L is the volume of carbon dioxide released.
Work Step by Step
1. Apply the law of conservation of mass to this chemical reaction:
m ( calcium carbonate) + m ( hydrochloric acid) = m (solution) + m (carbon dioxide)
Note: we can find the mass of hydrochloric acid as we are given volume and density:
m ( hydrochloric acid) = d x V
m ( hydrochloric acid) = 1.096 g/mL x 50.0 mL
m ( hydrochloric acid) = 54.8 g
Replace m of calcium carbonate, m of hydrochloric acid, and m of solution, to find m of carbon dioxide:
10 g + 54.8 g = 60.4 g + m (carbon dioxide)
m (carbon dioxide) = 64.8 g - 60.4 g
m (carbon dioxide) = 4.4 g
2. Find the volume of 4.4 g carbon dioxide, when we know the density 1.798g/L.
d = $\frac{m}{V}$ , we can write the formula to find the volume : V = $\frac{m}{d}$
V = $\frac{4.4 g }{1.798g/L}$
V = 2.447 L
V = 2.4 L
