Answer
d = 0.92 g/cm3.
mass of 400.4 mL ice, m = 368.41 g
Work Step by Step
Volume of ice cube: V= $(edge)^{3}$
V= $(3.5 cm)^{3}$
V = 42.88 cm3
a. Density of ice:
d = $\frac{m}{V}$
d = $\frac{39.45 g}{42.88 cm3}$
d = 0.92 g/cm3
b. Calculate the mass of 400.4 mL water in ice cube:
m = d x v
m = 0.92 g/cm3 x 400.4mL ( we know 1 cm3 = 1 mL)
m= 0.92 g/mL x 400.4mL
m = 368.41 g
