Answer
V = 2.4 L is the volume of hydrogen sulfide.
Work Step by Step
1. Apply the law of conservation of mass to this chemical reaction:
m ( zinc ore) + m ( sulfuric acid) = m (solution) + m (hydrogen sulfide)
Note: we can find the mass of sulfuric acid as we are given volume and density:
m ( sulfuric acid) = d x V
m ( sulfuric acid) = 1.153 g/mL x 50.0 mL
m ( sulfuric acid) = 57.65 g
m ( sulfuric acid) = 57.7 g
Replace m of zinc ore, m of sulfuric acid, and m of solution, to find m of hydrogen sulfide:
10.8 g + 57.7 g = 65.1 g + m (hydrogen sulfide)
m (hydrogen sulfide) = 68.5 g - 65.1 g
m (hydrogen sulfide) = 3.4 g
2. Find the volume of 3.4 g hydrogen sulfide, when we know the density 1.393 g/L.
d = $\frac{m}{V}$ , we can write the formula to find the volume : V = $\frac{m}{d}$
V = $\frac{3.4 g }{1.393g/L}$
V = 2.441 L
V = 2.4 L
