Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 13 - Properties of Solutions - Exercises: 13.43b

Answer

$1.12\;M\;LiClO_4\bullet3H_2O$

Work Step by Step

Molarity is defined as moles solute per liter of solution. First, we must find the number of moles of LiClO4*3H2O. We will first need the molar mass from the periodic table: $160.44\;\frac{g}{mol}\;LiClO_4\bullet3H_2O$ Next, convert to moles: $(22.4\;g\;LiClO_4\bullet3H_2O)\times(\;\frac{1\;mol}{160.44\;g})$ $0.1396\;mol$ Next, convert to liters of solution: $125\;mL = 0.125\;L$ Now, utilize molarity formula $M=\frac{0.1396\;mol\;solute}{0.125\;L\;solution}$ $1.12\;M\;LiClO_4\bullet3H_2O$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.