Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 13 - Properties of Solutions - Exercises: 13.41c


2.48 molal

Work Step by Step

Molality is found as moles of solute over kilograms of solvent. In this case, the solute is the CH3OH and the solvent is the water. From part a, the molar mass of CH3OH is 32 so we have: 14.6g * (1mol/32g) = 0.456 mol Then we have 184g of H2O, which is 0.184 kg Therefore, the molality would be 0.456mol/0.184kg = 2.48 molal
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.