Chemistry: The Central Science (13th Edition)

by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.

Published by Prentice Hall

ISBN 10: 0321910419

ISBN 13: 978-0-32191-041-7

Chapter 13 - Properties of Solutions - Exercises - Page 568: 13.41c

Answer

2.48 molal

Work Step by Step

Molality is found as moles of solute over kilograms of solvent. In this case, the solute is the CH3OH and the solvent is the water. From part a, the molar mass of CH3OH is 32 so we have: 14.6g * (1mol/32g) = 0.456 mol Then we have 184g of H2O, which is 0.184 kg Therefore, the molality would be 0.456mol/0.184kg = 2.48 molal

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