Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 13 - Properties of Solutions - Exercises: 13.41a

Answer

0.0427

Work Step by Step

We have 14.6 g of CH3OH per 184g of H2O. To find the mole fraction, we need to convert both to moles: CH3OH (Carbon is 12g/mol, H is 1g/mol, O is 16g/mol): 12 + 3*1 + 16 + 1 = 32 g/mol H2O : 2*1 + 16 = 18 g/mol Then we have 14.6 g * (1mol/32g) = 0.456 moles CH3OH and then 184g * (1mol/18g) = 10.22 moles H2O The total moles is 10.22 + 0.456 = 10.678 moles so then the mole fraction of CH3OH would be moles CH3OH/ total moles 0.456 / 10.678 = 0.0427
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