Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 13 - Properties of Solutions - Exercises: 13.39a

Answer

$2.15 \% \; Na_2SO_4$

Work Step by Step

Mass percentage = mass solute / mass solution * 100 Mass solute = 10.6 g Na$_2$SO$_4$ Mass solution = (10.6 g Na$_2$SO$_4$ + 483 g H2O) $10.6\div(10.6+483)\times100=2.147$ Rounding to appropriate significant figures: 2.15% Na$_2$SO$_4$
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