Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 13 - Properties of Solutions - Exercises - Page 568: 13.41b

Answer

$7.35\%\;CH_3OH$

Work Step by Step

mass percent: $\frac{mass\;solute}{mass\;solution}\times100$ substituting values: $\frac{14.6\;g\;CH_3OH}{14.6\;g\;CH_3OH+184\;g\;H_2O}\times100$ Evaluating and rounding with significant figures: $7.35\%\;CH_3OH$
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