Answer
The final volume of that $CaCl_2$ solution is equal to 72 mL.
Work Step by Step
1. Write the dilution expression, and rearrange it to solve for "$V_2$":
$C_1V_1 = C_2V_2$
- Divide both sides by "$C_2$":
$\frac{C_1V_1}{C_2} = V_2$
$ V_2 = \frac{C_1V_1}{C_2}$
2. Substitute the given values, and calculate the value of the final volume.
$ V_2 =\frac{(4.0 \% \space (m/v))(18 \space mL)}{1.0 \% \space (m/v)}$
$V_2 = 72 \space mL$