Answer
The volume required to prepare that solution using a $12.0$ $M$ $H_2SO_4$ solution is equal to 5.21 mL.
Work Step by Step
1. Write the dilution expression, and rearrange it to solve for "$V_1$":
$C_1V_1=C_2V_2$
- Divide both sides by "$C_1$":
$V_1 = \frac{C_2V_2}{C_1}$
2. Substitute the given values, and calculate the value of the initial volume.
$V_1=\frac{(2.50 \space M)(25.0 \space mL)}{12.0 \space M}$
$V_1 = 5.21 \space mL$