Answer
The final concentration of that $H_2SO_4$ solution is equal to 3.0% (m/v).
Work Step by Step
1. Write the dilution expression, and rearrange it to solve for "$C_2$":
$C_1V_1 = C_2V_2$
- Divide both sides by "$V_2$":
$\frac{C_1V_1}{V_2} = C_2$
$ C_2 = \frac{C_1V_1}{V_2}$
2. Substitute the given values, and calculate the value of the final concentration.
$ C_2 =\frac{(15\% (m/v))(50.0 \space mL)}{250 \space mL}$
$C_2 = 3.0 \% \space (m/v)$