Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 9 - Section 9.5 - Dilution of Solutions - Questions and Problems - Page 304: 9.59c

Answer

The volume required to prepare that solution using a $8.00$ $M$ $KCl$ solution is equal to 1.88 mL.

Work Step by Step

1. Write the dilution expression, and rearrange it to solve for "$V_1$": $C_1V_1=C_2V_2$ - Divide both sides by "$C_1$": $V_1 = \frac{C_2V_2}{C_1}$ 2. Convert the final volume ($V_2$) to milliliters: $0.100 \space L \times \frac{1000 \space mL}{1 \space L} = 100. \space mL$ 3. Substitute the given values, and calculate the value of the initial volume. $V_1=\frac{(0.150 \space M)(100. \space mL)}{8.00 \space M}$ $V_1 = 1.88 \space mL$
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