Answer
The volume required to prepare that solution using a $10.0$ $M$ $NH_4Cl$ solution is equal to 75.0 mL.
Work Step by Step
1. Write the dilution expression, and rearrange it to solve for "$V_1$":
$C_1V_1=C_2V_2$
- Divide both sides by "$C_1$":
$V_1 = \frac{C_2V_2}{C_1}$
2. Convert the final volume $(V_2)$ to milliliters:
$0.500 \space L \times \frac{1000 \space mL}{1 \space L} = 500 \space mL$
3. Substitute the given values, and calculate the value of the initial volume.
$V_1=\frac{(1.50 \space M)(500 \space mL)}{10.0 \space M}$
$V_1 = 75.0 \space mL$
