Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 7 - Section 7.3 - The Ambiguous Case - 7.3 Problem Set - Page 389: 8

Answer

$B = 90^\circ$

Work Step by Step

$\sin{B} = \dfrac{b \sin{A}}{a} = \dfrac{12 \times \sin{30^\circ}}{6} $ $\sin{B} = 1$ $B = 90^\circ$ $B' = 180-B = 90^\circ = B$
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