Answer
$B = 90^\circ$
Work Step by Step
$\sin{B} = \dfrac{b \sin{A}}{a} = \dfrac{12 \times \sin{30^\circ}}{6} $
$\sin{B} = 1$
$B = 90^\circ$
$B' = 180-B = 90^\circ = B$
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