Answer
$B = 77^\circ$
$B' =103^\circ$
Work Step by Step
$\sin{B} = \dfrac{b \sin{A}}{a} = \dfrac{18 \times \sin{60^\circ}}{16} $
$\sin{B} = 0.974$
$B = 77^\circ$
$B' = 180-B = 103^\circ$
$A+B' =60+103 = 163^\circ <180$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 7 - Section 7.3 - The Ambiguous Case - 7.3 Problem Set - Page 389: 9
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