Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 7 - Section 7.3 - The Ambiguous Case - 7.3 Problem Set - Page 389: 5

Answer

See the steps.

Work Step by Step

$\sin{B} = \dfrac{b \sin{A}}{a} = \dfrac{30 \times \sin{150^\circ}}{10} $ $\sin{B} = 1.5$ There is no value of $B$ for which $\sin{B}$ is greater than 1. $\therefore$ There is no solution possible for the triangle.
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