Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 7 - Section 7.3 - The Ambiguous Case - 7.3 Problem Set - Page 389: 12

Answer

$B = 54.49^\circ \hspace{10pt} C= 82.51^\circ \hspace{10pt} c =45.06 ft$ $B' =125.51^\circ \hspace{10pt} C'=11.49^\circ \hspace{10pt} c' = 9.054 ft$

Work Step by Step

$\sin{B} = \dfrac{37 \times \sin{43^\circ}}{31} = 0.814$ $B = 54.49^\circ \hspace{40pt} B' =180-B= 125.51^\circ $ $C = 180-(A+B) = 82.51^\circ$ $c = \dfrac{31 \times \sin{82.51^\circ}}{\sin{43}} = 45.06 ft$ $C'= 180-(A+B') = 11.49^\circ$ $c' = \dfrac{31 \times \sin{11.49^\circ}}{\sin{43}} = 9.054 ft$
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