Answer
$B = 54.2^\circ \hspace{10pt} C= 87.8^\circ \hspace{10pt} c =66.55 ft$
$B' =125.8^\circ \hspace{10pt} C'=16.2^\circ \hspace{10pt} c' = 18.58 ft$
Work Step by Step
$\sin{B} = \dfrac{54 \times \sin{38^\circ}}{41} = 0.811$
$B = 54.2^\circ \hspace{40pt} B' =180-B= 125.8^\circ $
$C = 180-(A+B) = 87.8^\circ$
$c = \dfrac{41 \times \sin{87.8^\circ}}{\sin{38}} = 66.55 ft$
$C'= 180-(A+B') = 16.2^\circ$
$c' = \dfrac{41 \times \sin{16.2^\circ}}{\sin{38}} = 18.58 ft$
