Answer
Amplitude is 1
period is 4$\pi$
Horizontal shift is 0
Work Step by Step
Using the base function $f(t)=a\cdot $sin$(k(t-b))$, the amplitude is $|a|$ which is 1 in this example. The period is found using $\frac{2\pi}{k}$, so $\frac{2\pi}{1/2}=4\pi$. And the horizontal shift is represented by $b$, which, in this case, is $0$.
