Answer
(a) $\frac{\pi}{4}$
(b) $P(-\frac{\sqrt 2}{2},-\frac{\sqrt 2}{2})$
(c) $sin(t)=-\frac{\sqrt 2}{2}, cos(t)=-\frac{\sqrt 2}{2},tan(t)=1,cot(t)=1,sec(t)=-\sqrt 2,csc(t)=-\sqrt 2$
Work Step by Step
(a) Draw a diagram with $t=-\frac{11\pi}{4}$, we can see that it will end up in Quadrant III, and the reference number for t is $\bar t=3\pi-\frac{11\pi}{4}=\frac{\pi}{4}$
(b) With the results from (a) and table 4 on page 404 in the book, we have $P(-\frac{\sqrt 2}{2},-\frac{\sqrt 2}{2})$
(c) Based on the above results, $sin(t)=y=-\frac{\sqrt 2}{2}, cos(t)=x=-\frac{\sqrt 2}{2},tan(t)=\frac{y}{x}=1,cot(t)=\frac{x}{y}=1,sec(t)=\frac{1}{x}=-\sqrt 2,csc(t)=\frac{1}{y}=-\sqrt 2$
