Answer
$$\frac{sin \space t}{\sqrt{1 - sin^2 \space t}}$$
Work Step by Step
$$tan \space t$$
Using: $tan \space t = \frac{sin \space t}{cos \space t}$
$$\frac{sin \space t}{ cos \space t}$$
Using: $sin^2\space t + cos^2\space t= 1 $
$cos^2 \space t = 1 - sin^2\space t$
$cos \space t = \pm \sqrt{1- sin^2 \space t}$
Notice: For "t" in Quadrant IV, cos t is always positive, thus:
$cos \space t = +\sqrt {1 - sin^2 \space t}$
$$\frac{sin \space t}{\sqrt{1 - sin^2 \space t}}$$
