Answer
$tan \space t = -\frac{5}{12}$
$csc \space t = \frac{13}{5}$
$sec \space t = -\frac{13}{12}$
$cot \space t = -\frac{12}{5}$
Work Step by Step
$$tan \space t = \frac{sin \space t}{cos \space t} = \frac{5/13}{-12/13} = - \frac 5{12}$$ $$csc \space t = \frac{1}{sin\space t} = \frac{1}{5/13} = \frac {13} 5$$ $$sec \space t = \frac{1}{cos \space t} = \frac{1}{-12/13} = -\frac {13}{12}$$ $$cot \space t = \frac{1}{tan\space t} = \frac{1}{-5/12} = -\frac {12} 5$$
